[PD] Non-Linear Quantization / Bitcrush

[Ludwig Maes]

The reason you use the inverse is so that the amplitude remains the
same albeit quantized. The reason we use another function before
flooring is to distritube the floor levels.But afterwards we need to
bring the values back to their "original" place

On 2 November 2010 19:37, Ludwig Maes <ludwig.maes at gmail.com> wrote:
> So you want amplitude 'a' dependant quantization size 'q' ? take your
> chosen q(a); in your example it seems you want a simple line:
> q=q(0)-k*a;
> define f(a) as integral of 1/q from a=0 to a; also calculate the
> inverse of f(a) i.e. a(f);
>
> now for each sample do: out=a(round(f(in))) where round is any floor
> or the like...
>
> have fun!
>
> ps:
>
> in your example: q=q0-k*a with for example q(0)=0.001 and
> q(0.8)=0.0001: q:=0.001-0.0009/0.8*a
> then f=2558.427881-1111.111111*ln(10.-9.*a)
> and inverse=easy
>
>
> On 2 November 2010 19:20, Ludwig Maes <ludwig.maes at gmail.com> wrote:
>> This is pretty easy actually, I use such things mostly to guide my
>> rhythmical quantization...
>>
>> On 2 November 2010 19:19, brandon zeeb <zeeb.brandon at gmail.com> wrote:
>>> This is even better.  If I could minimize the jumps around Y = 0.5 to -0.5
>>> It'll be exactly what I'm looking for... or a start at least.
>>>
>>> Do you see what I mean now?  See how the amount of quantization changes with
>>> Y and a minimum quantization value?
>>>
>>> I think I'm getting towards the answer now...
>>>
>>> --
>>> Brandon Zeeb
>>> Columbus, Ohio
>>>
>>>
>>
>