[PD] symbol to float

[hans w. koch]

thanks cyrille,

but the symbol 8.689756393432365 throws an "$1: argument number out of range“ error.
by putting a „list prepend“ before the message box it works.

best hans

> Am 21.04.2017 um 15:58 schrieb cyrille henry <ch at chnry.net>:
> 
> hello,
> 
> if you want the conversion to be in 0 logical time, you can write the symbol in a textfile, and read it back.
> 
> something like :
> [clear, add $1, write /tmp/symbol2float, read /tmp/symbol2float, rewind, bang<
> |
> [textfile]
> 
> but since it need to write the data somewhere, it's still not an ideal solution.
> 
> cheers
> Cyrille
> 
> 
> Le 21/04/2017 à 15:40, hans w. koch a écrit :
>> hello,
>> 
>> pd-vanilla question:
>> trying to harness geodata from an xml file, i need to parse lines like this: <gx:coord>8.689756393432365 49.4138 109.18</gx:coord>
>> with a combination of "list split“ and „list fromsymbol“ i end up with three message boxes, „8.689756393432365“, „49.4138“ and „109.18“.
>> problem is, that the message box containing „8.689756393432365“ is a symbol and i can´t seem to find a way to reconvert it to a float, other then sending it thru a netsend/netreceive pair.
>> (as per this tip from 2007: https://lists.puredata.info/pipermail/pd-list/2007-02/047499.html).
>> 
>> its working fine, but i was wondering, if this really is the only vanilla solution?
>> 
>> i might well be staring at the obvious and not seeing it...
>> thanks in advance for any other pointers!
>> 
>> best hans
>> 
>> www.hans-w-koch.net
>> 
>> 
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