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<div>Not that I don't appreciate the snide commentary, but this is why I'm asking. You can't forget the sin*sin part. i stands for "imaginary". (slowly: i is "imaginary"). Turning the product of sines into the negative product of sines is imaginary. There is no number that, squared, equals -1. There is no number that, squared, equals -1. It's not really there.
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<blockquote class="gmail_quote" style="PADDING-LEFT: 1ex; MARGIN: 0px 0px 0px 0.8ex; BORDER-LEFT: #ccc 1px solid">Date: Mon, 07 Nov 2005 20:58:36 +0100<br>From: Piotr Majdak <<a href="mailto:piotr@majdak.com">piotr@majdak.com
</a>><br>Subject: Re: [PD] basic DSP stuff<br>Cc: Pure Data List <<a href="mailto:pd-list@iem.at">pd-list@iem.at</a>><br>Message-ID: <<a href="mailto:436FB1EC.80908@majdak.com">436FB1EC.80908@majdak.com</a>>
<br>Content-Type: text/plain; charset=us-ascii; format=flowed<br><br>Chuckk Hubbard wrote:<br>> i*sin(a) and i*sin(b) multiply to -sin(a)sin(b)?<br><br>let's forget the sin*sin and look at the i*i part only: since i =<br>
sqrt(-1) by definition, i*i is -1 (slowly: i*i= sqrt(-1)*sqrt(-1) =<br>sqrt(-1 * -1) = sqrt((-1)^2) = -1)<br><br>Thus, i*sin(a) * i*sin(b) = -1 * sin(a)*sin(b)<br><br>br, piotr<br><br><br><br>------------------------------
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