what's the easiest way for pd to find the nearest power of 2 for any float? <br><br>so 10 would give a result of 8, <br>53 would give a result of 64,<br><br>etc..<br><br><br><a href="http://en.wikipedia.org/wiki/Power_of_two#Algorithm_to_convert_any_number_into_nearest_power_of_two_number">http://en.wikipedia.org/wiki/Power_of_two#Algorithm_to_convert_any_number_into_nearest_power_of_two_number</a><br>
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