Very nice.<br><br>Cheers Andy,<br><br>Jbz<br><br><div class="gmail_quote">On Sat, Aug 1, 2009 at 5:43 PM, Andy Farnell <span dir="ltr"><<a href="mailto:padawan12@obiwannabe.co.uk">padawan12@obiwannabe.co.uk</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;"><br>
Hi JBeez,<br>
<br>
We could interpret this in two ways. A hard constraint is applied by<br>
using [moses] [max], [min] or [clip] so that numbers outside the<br>
desired bounds are simply discarded, or clamped to the boundry.<br>
Look that one up in the help files if it's what you want.<br>
<br>
On the other hand, I think you really mean to rescale the numbers<br>
so that all of them fit between your new bounds.<br>
<br>
Changing a range requires a linear scale function. There<br>
is one called [scale].<br>
<br>
But, instead of just using a ready made abstraction maybe it's<br>
a good idea to understand the simple principle of changing the<br>
slope and origin of a line.<br>
<br>
If your original bounds are 800 and 19000 then the magnitude<br>
of the range, the interval, is 19000 - 800 = 18200<br>
<br>
The origin of the interval is 800, which is the lowest<br>
number you can have.<br>
<br>
The first thing to do is 'reset the origin' so that all<br>
your numbers have a lowest value starting at zero, so<br>
to do that subtract 800.<br>
<br>
Then scale the line to cover the magnitude of your new interval,<br>
which is 800 - 400 = 400<br>
<br>
To map 18200 to 400 divide them to get 400/18200 = 0.021987<br>
<br>
Now scale the numbers by that factor<br>
<br>
Finally add the bottom offset, your new origin, by adding<br>
the lowest value of the new range which is 400<br>
<br>
So the complete scale function is now<br>
<br>
((x - 800) * 0.021987) + 400<br>
<br>
(see attached patch)<br>
<br>
<br>
a.<br>
<br>
<br>
On Sat, 1 Aug 2009 15:32:06 +0100<br>
J bz <<a href="mailto:jbeezez@googlemail.com">jbeezez@googlemail.com</a>> wrote:<br>
<br>
> Dear all a y'all,<br>
><br>
> I have a list of 25 numbers between 800-19000 that I'm calling randomly'ish.<br>
><br>
> I want to add some constraints to those numbers:<br>
> so for example, I have the number 6569 and by the use of either simple x2<br>
> multiplication or dividing I want to shoehorn it into the ranges of<br>
> 11000-18000 but also 400-800 at the same time.<br>
><br>
> THe ranges are set but the numbers aren't. So say sometimes the range<br>
> 2400-4700 may get a number that is less than the range like 912 and<br>
> sometimes it will get a number over the range like 13264, so I need a way of<br>
> Pd recognising whether the number requires multiplication or dividing.<br>
><br>
> How can I do this?<br>
><br>
> Bests,<br>
><br>
> Jbz<br>
><br>
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