<meta http-equiv="content-type" content="text/html; charset=utf-8"><span class="Apple-style-span" style="font-family: arial, sans-serif; font-size: 15px; border-collapse: collapse; ">Hi Ed!<div><br></div><div>Thanks for sharing this patch, i remember when you did show this project.</div>
<div>Here is missing [0_maker_1] abstraction in the package.</div><div>Cheers, </div><div>Cristiano</div><div><br></div></span><br><div class="gmail_quote">On Wed, Sep 1, 2010 at 8:06 PM, Ed Kelly <span dir="ltr"><<a href="mailto:morph_2016@yahoo.co.uk">morph_2016@yahoo.co.uk</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex;">Yes, that's what I meant to say. Radians is only for the [tan], but it's quite<br>
useful elsewhere.<br>
I have been feeling guilty all day, for the archives being wrong-headed :) from<br>
me.<br>
<br>
I have a nice trig patch now :) maybe I should submit a good trig patch to GEM<br>
documentation. Perhaps we could help - since many artists struggle with this (my<br>
math teacher at school was really intimidating!)<br>
<br>
But, I have noticed a sinusoidal error with the graphics in my patch. So, here<br>
is the real thing!<br>
<br>
It's my notation system. I was trying to keep it a secret until it is entirely<br>
ready, but open source projects demand open-source solutions, so here's the<br>
current prototype. Notice that when you move the second note up and down, there<br>
is a sinusoidal error in the [shearYX] -ed half-beam sheared rectangles. Is<br>
there any way to calculate this and compensate for it? I must have missed<br>
something...<br>
<br>
...Classical players can be quite particular about such issues! I want it to<br>
look good.<br>
<br>
PS - For the Brazilians I showed this to, I love you and will deliver this soon.<br>
<br>
X<br>
Ed<br>
Metastudio 3 for Pure Data - Free download at:<br>
<a href="http://sharktracks.co.uk/puredata" target="_blank">http://sharktracks.co.uk/puredata</a><br>
<br>
<br>
<br>
----- Original Message ----<br>
From: cyrille henry <<a href="mailto:ch@chnry.net">ch@chnry.net</a>><br>
To: Ed Kelly <<a href="mailto:morph_2016@yahoo.co.uk">morph_2016@yahoo.co.uk</a>><br>
Cc: Claude Heiland-Allen <<a href="mailto:claudiusmaximus@goto10.org">claudiusmaximus@goto10.org</a>>; PD List <<a href="mailto:pd-list@iem.at">pd-list@iem.at</a>><br>
Sent: Wed, 1 September, 2010 20:44:56<br>
Subject: Re: [PD] GEM Shear / angle relationship<br>
<br>
<br>
<br>
Le 01/09/2010 10:37, Ed Kelly a écrit :<br>
> Thanks for unlocking my broken trig head.<br>
><br>
> This should really be in the documentation. The angle is in radians. Patch<br>
> enclosed...<br>
no, the angle is not in radian.<br>
in fact, shear is a non rotational space distortion, there is no angle...<br>
<br>
shear distord 1 direction in relation to the coordinate on a 2nd direction.<br>
As Claude explain, you can calculate an angle from this distortion, based on 2<br>
dimension. The tan object is in radian. that's the only thing in radian.<br>
<br>
Cyrille<br>
<br>
<br>
<br>
><br>
> Best,<br>
> Ed<br>
><br>
> Metastudio 3 for Pure Data - Free download at:<br>
> <a href="http://sharktracks.co.uk/puredata" target="_blank">http://sharktracks.co.uk/puredata</a><br>
><br>
><br>
><br>
> ----- Original Message ----<br>
> From: Claude Heiland-Allen<<a href="mailto:claudiusmaximus@goto10.org">claudiusmaximus@goto10.org</a>><br>
> To: Ed Kelly<<a href="mailto:morph_2016@yahoo.co.uk">morph_2016@yahoo.co.uk</a>><br>
> Cc: PD List<<a href="mailto:pd-list@iem.at">pd-list@iem.at</a>><br>
> Sent: Wed, 1 September, 2010 1:09:43<br>
> Subject: Re: [PD] GEM Shear / angle relationship<br>
><br>
> Hi Ed,<br>
><br>
> On 31/08/10 15:31, Ed Kelly wrote:<br>
>> Can anyone tell me how to calculate the 'shear' value (when using [shearYX]<br>
in<br>
>> Gem) from an angle (degrees or radians, I don't mind)?<br>
><br>
> This is just a guess, for one direction of shear in 2D space:<br>
><br>
> shear = tan(angle) (the angle marked ** in the ascii diagram below)<br>
><br>
> | __________<br>
> |**/ /<br>
> | / /<br>
> |/_________/<br>
><br>
><br>
> (because tan(0) = 0, tan(45deg) = 1, tan(90deg) = inf)<br>
><br>
> Otherwise try drawing triangles and doing some trigonometry<br>
> (in a right-angle triangle:<br>
> sin=opposite/diagonal<br>
> cos=adjacent/diagonal<br>
> tan=opposite/adjacent<br>
> )<br>
><br>
><br>
> Claude<br>
> -- <a href="http://claudiusmaximus.goto10.org" target="_blank">http://claudiusmaximus.goto10.org</a><br>
><br>
><br>
><br>
><br>
><br>
><br>
><br>
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<br></blockquote></div><br>