<br>By the way, there's a way to draw a circle using nothing but addition: <a href="http://en.wikipedia.org/wiki/Midpoint_circle_algorithm">http://en.wikipedia.org/wiki/Midpoint_circle_algorithm</a><br><br>Implementing this in Pd is completely impractical, but it's fun to think about.<br>
Cheers,<br> Peter<br><br><br><div class="gmail_quote">On Sat, Apr 9, 2011 at 2:12 AM, Mathieu Bouchard <span dir="ltr"><<a href="mailto:matju@artengine.ca">matju@artengine.ca</a>></span> wrote:<br><blockquote class="gmail_quote" style="margin: 0pt 0pt 0pt 0.8ex; border-left: 1px solid rgb(204, 204, 204); padding-left: 1ex;">
<div class="im">On Fri, 8 Apr 2011, Tyler Leavitt wrote:<br>
<br>
<blockquote class="gmail_quote" style="margin: 0pt 0pt 0pt 0.8ex; border-left: 1px solid rgb(204, 204, 204); padding-left: 1ex;">
I am trying to graph a section of a circle into an array. I have been trying to wrap my head around [sin] and [cos] but none of my configurations get results. If you had a circle with radius 100 with a center at (0, 0) I'm trying to get the upper right quadrant (positive x and positive y). The start point being (100,0) and the end point being (0,100).<br>
<br>
Any ideas on moving forward?<br>
</blockquote>
<br></div>
use angles between 0 and pi/2 = 1.5708<br>
<br>
putting those into [cos] and [sin] will give you values for a circle of radius 1 at (0,0). For different radiuses you apply [*] after that.<br>
<br>
quadrants and clockwiseness depend on which axis uses [cos], which axis uses [sin], and which direction of each axis is positive. There are several standards for those things.<br>
<br>
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