<html><body><div style="color:#000; background-color:#fff; font-family:HelveticaNeue, Helvetica Neue, Helvetica, Arial, Lucida Grande, sans-serif;font-size:12pt">Hi Pall,<br> Which help patches? I haven't seen a single help patch that substitutes strings of [+~] to double the incoming signal where a simple multiplication would do.<br><br>I have seen cascades of [+~] for additive synthesis, but that's not the same.<br><br>-Jonathan<br><div style="display: block;" class="yahoo_quoted"> <br> <br> <div style="font-family: HelveticaNeue, Helvetica Neue, Helvetica, Arial, Lucida Grande, sans-serif; font-size: 12pt;"> <div style="font-family: HelveticaNeue, Helvetica Neue, Helvetica, Arial, Lucida Grande, sans-serif; font-size: 12pt;"> <div dir="ltr"> <font face="Arial" size="2"> On Saturday, January 18, 2014 1:00 PM, Pall Thayer <pallthay@gmail.com> wrote:<br> </font> </div> <div class="y_msg_container"><div
id="yiv3146524614"><div dir="ltr">Ah... I've seen this in some of the help patches. Why would someone do it with multiple [+~] instead of a single [*~]? There's no difference?</div><div class="yiv3146524614gmail_extra"><br><br><div class="yiv3146524614gmail_quote">
On Sat, Jan 18, 2014 at 12:49 PM, IOhannes m zmölnig <span dir="ltr"><<a rel="nofollow" ymailto="mailto:zmoelnig@iem.at" target="_blank" href="mailto:zmoelnig@iem.at">zmoelnig@iem.at</a>></span> wrote:<br><blockquote class="yiv3146524614gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex;">
<div class="yiv3146524614im">On 01/18/2014 06:24 PM, Pall Thayer wrote:<br>
> Can anyone tell me what one is accomplishing when doing something like this:<br>
><br>
> [osc~ 440]<br>
> |<br>
> [+~]<br>
</div>> |\ x1<br>
> [+~]<br>
> |\ x2<br>
> [+~]<br>
> |\ x3<br>
> [+~]<br>
> x4<br>
<div class="yiv3146524614im">><br>
> In other words, the chain of [+~] that feed the previous object's output<br>
> into both inlets of the next... what does this do exactly?<br>
<br>
</div>it adds a signal with itself: y=x+x=2*x<br>
<br>
so the output of the 1st [+~] is<br>
x1=x0 (as the 2nd inlet~ is not connected)<br>
and the following [+~] will output:<br>
x2=x1+x1=2*x1=2*x0<br>
x3=x2+x2=2*x2=2*2*x0=4*x0<br>
x4=x3+x3=2*x3=2*4*x0=8*x0<br>
<br>
so you could write the patch as:<br>
<br>
[osc~ 440]<br>
|<br>
[*~ 8]<br>
<br>
<br>
more often you see [*~] instead of [+~], which is a simple way to square<br>
the input.<br>
<br>
fgmadsr<br>
<span class="yiv3146524614HOEnZb"><font color="#888888">IOhannes<br>
<br>
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<br></blockquote></div><br><br clear="all"><div><br></div>-- <br>*****************************<br>Pall Thayer<br>artist<br><a rel="nofollow" target="_blank" href="http://pallthayer.dyndns.org/">http://pallthayer.dyndns.org</a><br>*****************************
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