<div dir="ltr">>> [fexpr~ abs($x[0] - $x[-1]) > 0.5]<div>>> [threshold~ 0.5 0 0.5 0]</div><div><br></div><div>sick</div></div><br><div class="gmail_quote"><div dir="ltr" class="gmail_attr">On Sat, Mar 2, 2019 at 7:31 PM Alexandre Torres Porres <<a href="mailto:porres@gmail.com">porres@gmail.com</a>> wrote:<br></div><blockquote class="gmail_quote" style="margin:0px 0px 0px 0.8ex;border-left:1px solid rgb(204,204,204);padding-left:1ex"><div dir="ltr"><div dir="ltr"><div dir="ltr">connect output of [phasor~] into:</div><div dir="ltr"><div><br></div><div>[fexpr~ abs($x[0] - $x[-1]) > 0.5]<br></div><div><br></div><div>then use:</div><div><br></div><div>[threshold~ 0.5 0 0.5 0]</div></div></div></div><br><div class="gmail_quote"><div dir="ltr" class="gmail_attr">Em sáb, 2 de mar de 2019 às 11:05, Claude Heiland-Allen <<a href="mailto:claude@mathr.co.uk" target="_blank">claude@mathr.co.uk</a>> escreveu:<br></div><blockquote class="gmail_quote" style="margin:0px 0px 0px 0.8ex;border-left:1px solid rgb(204,204,204);padding-left:1ex">On 2019-03-02 13:20, Orm Finnendahl wrote:<br>
>  is there some easy way in vanilla pd to get a bang on each phasor~<br>
> wraparound which doesn't involve polling with snapshot~?<br>
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</blockquote></div><br clear="all"><div><br></div>-- <br><div dir="ltr" class="gmail_signature"><div dir="ltr"><div><div dir="ltr"><div>____________________<br>m.e.grimm, m.f.a, ed.m.</div><div>cornell u., tc3</div><div><a href="http://megrimm.net" target="_blank">megrimm.net</a><br>____________________</div></div></div></div></div>