[PD] timer problem

[richard.bowers]

Thanks VERY much, Johannes. I hope to learn from these basic problems.

Best wishes,

Richard.


| hi
|
| the first inlet starts counting, the second one triggers the output ot the
| time that has elapsed since counting was started.
| therefore you have to make sure, that you trigger the second inlet before
| the first one (so that you read out the elapsed time, before you reset it
| to zero)
| with good look you can do this they way you tried:
| make a |bang( and a |timer| object.
| FIRST connect the |bang( outlet with the SECOND inlet of the |timer|
| THEN connect the |bang( outlet with the FIRST inlet of the |timer|
| but this is VERY BAD STYLE (and maybe it will stop working sometimes in
| the future. who knows ?)
|
| the clean solution would be
| =-----
| |bang(
| =-----
| |
| =------
| |t b b|
| =-----=
| |     |
| =-----=
| |timer|
| =------
| |
| =------------
| |print delta|
| -------------
|
| the trigger-object ("t", "trigger") makes sure that its outlets are
| triggered from right to left (outlet on the right hand comes first, the
| leftest one will be the last)
|
| everytime you must assure that messages are send in a special order, you
| really HAVE to use the trigger-method (though you could might get it to
| work, as i have shown above)
|
| make fun
| mfg.fsd.sad
| IOhannes
|
|
| On Wed, 23 May 2001, richard.bowers wrote:
|
| > Hi,
| >
| > I'm having a seriously fundamental problem here. I'm trying to use the
timer
| > to give the delta time for MIDI notes. The attached patch can only give
0
| > delta times because the bang goes into each inlet in quick succession.
| >
| > Can anyone offer a solution?
| >
| > Richard.
| >
|