[PD] rsqrt~

marius schebella marius.schebella at chello.at
Sun Apr 18 12:27:42 CEST 2004


hi siggmus,

it should work exactly as you described...
make sure, that you don't write a default value (like /~ 1) to the dividetilde, because then only messages ar accepted. 

marius.


On Sun, 18 Apr 2004 01:58:07 -0700
"siggmuss" <siggmus at fastmail.fm> wrote:

> hi, how can i make a reciprocal square root without using the rsqrt~
> object?
> i know rsqrt (x) = 1/sqrt(x)
> and im trying  [sig~ 1]-> [/~ ]<- [sqrt~ x] but i cant put signals to the
> right inlet of
> /~ , when i put an unsig~ it doesnt work , i need a signal because i want
> to connect the result to rifft~
> 
> any idea?
> 
> thanks in advance
> 
> siggmus
> 
> -- 
> http://www.fastmail.fm - One of many happy users:
>   http://www.fastmail.fm/docs/quotes.html
> 
> _______________________________________________
> PD-list mailing list
> PD-list at iem.at
> http://iem.at/cgi-bin/mailman/listinfo/pd-list




More information about the Pd-list mailing list