[PD] derivative function
Piotr Majdak
piotr at majdak.com
Tue Jun 27 09:51:01 CEST 2006
I forgot to send this here to the list _and_ frederico (again, damn)!
Federico wrote:
> -----BEGIN PGP SIGNED MESSAGE-----
> is there an object to compute the derivative function of a signal?
>
> don't know if derivative is the right term..
> i mean:
> f(x)=x => f'(x)=1
> f(x)=ln(x) => f'(x)=1/x
> f(x)=sin(x) => f'(x)=cos(x)
I don't know such as object, but maybe this will help you a little bit: Because
you're dealing with finite discrete signals, the derivative of a signal becomes
a difference between two consecutive samples. You can easily implement it using
[z~] (from zexy, I think) and then subtract the delayed and original sequence:
y[n]= x[n]-x[n-1]
> and a more question: has this anything to do with complex signals
I don't think so.
> or fourier?
It can, if you wish: derivative corresponds to a multiplication with a ramp in
the frequency domain. So, theoretically, you can transform your signal to the
frequency domain, multiple with a ramp
(watch for 2-sided spectrum), and then, back to time domain, you should have
something like "derivative". I have no idea if this works in practice :-)
Computation the group delay (=negative derivative of the phase) works using this
algorithm, compare
http://ccrma.stanford.edu/~jos/filters/Numerical_Computation_Group_Delay.html
br, Piotr
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