[PD] Can $0 be 0?
Miller Puckette
mpuckett at imusic1.ucsd.edu
Sun Aug 13 19:10:50 CEST 2006
That's funny... the reason $0 starts at 1000 and not 0 is because in
Max the $ variables were printffed into the boxes themselves and I
wanted to keep all the $ variables (at least the first 8999 of them)
to the same width as a character string.
Anyway, $0 uses true integers, so that it's unlikely they will ever reach
zero (you'd have to fill your address speace 100s of times)... so I think
you're safe.
cheers
Miller
On Sun, Aug 13, 2006 at 10:04:02AM +0200, Frank Barknecht wrote:
> Hi,
>
> I would like to check, if $0 was passed as an argument to an
> abstraction. The usual idiom is:
>
> [loadbang]
> |
> [f $1] assuming, $0 was passed as $1
> |
> [select 0]
> |
> this is $0 now
>
> Now of course this fails, if $0 also can be zero itself. I know, that
> currently this is very unlikely, because $0 starts at 1000 and grows.
> But it would be great if possible future changes to the
> $0-implementation would still rule out 0 as a value for $0, so that
> the test from above will keep working.
>
> Ciao
> --
> Frank Barknecht _ ______footils.org_ __goto10.org__
>
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