[PD] [*] vs [*~]

Kyle Klipowicz kyleklip at gmail.com
Wed Dec 27 18:19:10 CET 2006


Haha at first I didn't see who posted this and thought, 'what a newb...'

Now I'm thinking that some philosophic sparring of Pd fundamentals is about
to begin.  I'll make some popcorn and watch this one from the sidelines...

~Kyle


On 12/27/06, Mathieu Bouchard <matju at artengine.ca> wrote:
>
>
> I have some newbie questions here...
>
> why is it that [*] is only for floats, whereas if you want to multiply two
> signals one has to use [*~] ?
>
> And then why is it that [*~] can multiply a signal by a float, but [*]
> can't do that?
>
> And then why is it that [*~] can't multiply a float by a signal, the
> signal has to be on the left? Why is it that if I want to divide a float
> by a signal, then I have to explicitly cast the float to signal (using
> [sig~]) or use [expr~] ?
>
> _ _ __ ___ _____ ________ _____________ _____________________ ...
> | Mathieu Bouchard - tél:+1.514.383.3801 - http://artengine.ca/matju
> | Freelance Digital Arts Engineer, Montréal QC Canada
>
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