[PD] Expr does not play well with ints?

[B. Bogart]

Mathieu, are you really able to put 8.0 in an expr argument? In my PD
(.39 ubuntu package) the 8.0 gets turned into 8 and remains an int.

Hmm?

B. Bogart

Mathieu Bouchard wrote:
> On Mon, 23 Jul 2007, B. Bogart wrote:
> 
>> So I've been doing lots of calculations with expr and creation
>> arguments, and it seems to send an int when it should send a float way
>> too often:
>> [expr 8 / 20]
>> returns 0!!!
>> Have I lost my mind? Is my machine going crazy? or is expr actually
>> doing what I see here?
> 
> expr supports the int type because [expr] comes from jMax/FTS/Max/etc.
> So if you put a number without a dot it's parsed as an int. Then the
> main difference between ints and floats is that an int divided by an int
> is rounded towards zero (many languages do it like that but some others
> round it always downwards instead; some others instead force the result
> to be a float or a rational)
> 
> What you can do is either [expr 8 / 20.0] or [expr 8.0 / 20] or
> obviously [expr 8.0 / 20.0]
> 
> You only need to make one of the two as float because float has priority
> on int, so when a float comes into contact with an int, the int is
> converted, even though float can't represent everything that int can,
> e.g. compare
> 
>   [expr 123456789%10] finds last digit of 123456789
>   [expr int(123456789.0)%10] fails because float isn't that precise
> 
> do not put a space before % in that first example! if you do, pd will
> parse it as a number, turn it to float, then give it to [expr], which
> determines that float % int = syntax error.
> 
> cool, eh?
> 
>  _ _ __ ___ _____ ________ _____________ _____________________ ...
> | Mathieu Bouchard - tél:+1.514.383.3801, Montréal QC Canada
> 
> 
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