[PD] Expr does not play well with ints?

[Mathieu Bouchard]

On Mon, 23 Jul 2007, B. Bogart wrote:
>> Mathieu, are you really able to put 8.0 in an expr argument? In my PD
>> (.39 ubuntu package) the 8.0 gets turned into 8 and remains an int.
> Ah! [expr float(8) / 6] does the trick, I'm damn happy there is float()
> in there!!!

if you write any character next to the number that causes pd to read it 
as a symbol, then pd won't rewrite it before expr reads it.

[expr (8.0) / (6.0)] = 1.25
[expr 8.0 / 6.0]     = 1
[expr 8.0 /6.0]      = 1.25
[expr 8.0/ 6.0]      = 1.25
[expr 8.0/6.0]       = 1.25

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