[PD] Expr does not play well with ints?

Mathieu Bouchard matju at artengine.ca
Tue Jul 24 19:38:35 CEST 2007


On Tue, 24 Jul 2007, B. Bogart wrote:

> Ah, I see now.
> I could not use that method, since 8/6 was an example, and I wanted to
> do $8 / $6, so treating "$8" as a symbol would not have helped.

Ah, caution with that: literals like 8 6 8.0 6.0 and pd's substitutors ($1 
$2 $3) work in the same way in this case, but [expr]'s own substitutors 
($f1 $f2 $f3) don't have that int-vs-float confusion problem because then 
[expr] does not attempt to read those floats as being text.

  _ _ __ ___ _____ ________ _____________ _____________________ ...
| Mathieu Bouchard - tél:+1.514.383.3801, Montréal QC Canada


More information about the Pd-list mailing list