[PD] ADSR variations [was: Re: Patch-off]

[Jonathan Wilkes]

Hi Frank,
     I understand what you describe.  But when the 1st creation argument is a float, [list $1] and [list append $1] print the exact same result as far as I can see.

(Shaky comp sci terminology to follow...) Looking at list_new in x_list.c, if the first creation argument of [list $1 $2 etc.] is a not a symbol, the object is deemed a [list append] and the args are left alone.  For [list append $1 $2 etc.] however, after "append" is matched, the argument count is decremented and the 2nd arg becomes the 1st.  Consequently, the behavior of [list $1 $2 etc.] is exactly the same as [list append $1 $2 etc.] in this case.

-Jonathan

--- On Sun, 3/22/09, Frank Barknecht <fbar at footils.org> wrote:

> From: Frank Barknecht <fbar at footils.org>
> Subject: Re: [PD] ADSR variations [was: Re: Patch-off]
> To: pd-list at iem.at
> Date: Sunday, March 22, 2009, 12:27 PM
> Hallo,
> Jonathan Wilkes hat gesagt: // Jonathan Wilkes wrote:
> 
> > Actually [list $1 $2 $3 $4 $5] seems to work in this
> context, but I guess
> > that's because the first arg isn't a symbol. 
> Is that why you're saying [list
> > append] is needed?
> 
> The [list] object will behave differently depending on its
> first argument: You
> get to choose between [list prepend], [list append], [list
> split] etc. The
> following arguments have different meanings depending on
> the first argument.
> 
> E.g. [list split 3] will split a list at position 3, while
> [list prepend 3]
> will add a "3" in front of your incoming list.
> 
> If you create [list] without any argument it will be the
> same as [list append],
> but if you'd use [list $1] then the value of $1 will
> decide, which kind of list
> operation you get. So if $1 is "split" you get a
> splitter, if it's "append"
> then you get a [list append].
> 
> So [list $1 $2 $3 $4 $5] is *not* the same as [list append
> $1 $2 $3 $4 $5]!
> Try it by sending something into both and print the result.
> 
> Ciao
> -- 
> Frank
> 
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