[PD] imaginary numbers
matju at artengine.ca
Sat Aug 29 18:15:49 CEST 2009
On Sat, 29 Aug 2009, brandt at subnet.at wrote:
> and i tried to make sqrt from pd, but it does not like -1.
I'm sorry, I didn't explain this one. In the formulas I gave, "i"
represents square root of -1, but you can't use that as a number in pd
because pd only supports plain floats and not complex floats. But a
non-complex number system can be used to make a complex number system, and
the formulas are usually not very long.
A float can only be half of the data of a complex number. It's called
complex because it has two parts. The second float stands for the part
that is a multiple of "i", and the first float stands for the part that is
not. It's also often considered as a 2-D vector with extra operators, with
the x (cosine) standing for the real part, and the y (sine) standing for
the imaginary part.
But don't try to read the whole wikipedia articles on math topics, they're
huge and contain much stuff you don't need.
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