[PD] Re : connecting a samphold and a phasor together

Benoît Fortier benoitfortier at yahoo.ca
Wed Apr 28 18:10:53 CEST 2010

Thank you, I didn't knew about the one block delay. Problem solved very elegantly indeed!


De : Jack <jack at rybn.org>
À : Benoît Fortier <benoitfortier at yahoo.ca>
Cc : pd-list at iem.at
Envoyé le : Mer 28 avril 2010, 11 h 26 min 41 s
Objet : Re: [PD] connecting a samphold and a phasor together

I am not an expert in sound but with a [s~] (from [samphold~]) and a
[r~] (into [phasor~]), you should avoid dsp loop. [r~] receive with one
block delay.
Don't know if there is better solution.


Le mercredi 28 avril 2010 à 08:03 -0700, Benoît Fortier a écrit :
> First time on this mailing list, so hello everyone! I started using pd
> a couple of month ago and I'm completely addicted.
> Ok I have a simple problem for which I'm looking for the most elegant
> solution.
> I need a phasor (in a looping sampler) which frequency can be changed
> only at the beginning of it's period (when it drops to zero). That's
> usually the kind of problem a samphold can handle very well but when I
> connect a phasor and a samphold directly together I get a "dsp loop
> detected (some tilde objects not scheduled)" error. One solution could
> be to "pipe" the new frequency to the phasor with a delay calculated
> from the previous frequency but I have the feeling there must be a
> more elegant solution to this problem. Anyone got a suggestion? 
> There is a thread in the archive that is adressing a dsp loop issue
> but the solution proposed dosen't seem to be adapted to my specific
> problem.
> Thank you
> Benef
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