[PD] list operation

[cristiano figueiró]

thanks for the answers, i will try all and post the results ;)


On Tue, Apr 27, 2010 at 11:06 PM, Matt Barber <brbrofsvl at gmail.com> wrote:

> Ha ha, mine had a hilarious and totally unnecessary extra [list-map].
> That's what happens when you work hastily... how embarrassing; oh
> well.
>
> MB
>
> On Tue, Apr 27, 2010 at 9:13 PM, Jack <jack at rybn.org> wrote:
> > True, so now it should be OK (patch attached).
> > I didn't think of this eventuality.
> > ++
> >
> > Jack
> >
> >
> >
> > Le mardi 27 avril 2010 à 20:50 -0400, Matt Barber a écrit :
> >> One thing to watch out for;  if you get two items in the list that are
> >> equally as far as the test value, mine outputs one list with the value
> >> replacement at each appropriate index, while Jack's outputs several
> >> lists with the value replacement at only one index, but each
> >> replacement sequentially, if that makes any sense.
> >>
> >> So if the test value is 2.02, and the input list is <1 0 3 2 4 3 3 2 0
> >> 4>, mine will output:
> >>
> >> <1 0 3 2.02 4 3 3 2.02 0 4> as one list, while Jack's gives two lists:
> >>
> >> <1 0 3 2.02 4 3 3 2 0 4>
> >> <1 0 3 2 4 3 3 2.02 0 4>
> >>
> >> Matt
> >>
> >> On Tue, Apr 27, 2010 at 8:16 PM, Jack <jack at rybn.org> wrote:
> >> > An alternative. Also full pure-pd.
> >> > ++
> >> >
> >> > Jack
> >> >
> >> >
> >> >
> >> > Le mardi 27 avril 2010 à 18:49 -0400, Matt Barber a écrit :
> >> >> Try the attached (threw together using list-abs) -- right inlet is
> the
> >> >> value (12 in your example) and left inlet is the list of floats; I
> >> >> think this follows established list-abs syntax.
> >> >>
> >> >> It's possible that I overlooked a list-abs that already does this,
> and
> >> >> there is probably a step or two you could skip.
> >> >>
> >> >> You might get poor results if the list is a bang or contains symbols.
> >> >>
> >> >> Matt
> >> >>
> >> >>
> >> >> > Hello everyone,
> >> >> >
> >> >> > I would like to compare all the values in a list with a value of
> input and
> >> >> > then decide which is the closest value and replace that value
> closer to the
> >> >> > amount of input.
> >> >> >
> >> >> > For example, I have a list <2, 10, 35> and have an input value of
> <12> I
> >> >> > would like the list as output <2, 12, 35>. I'm almost getting, but
> the patch
> >> >> > is so ugly that I will not show here, i'm sure there is a more
> elegant
> >> >> > solution. Does anyone have an idea?
> >> >> > tnx ;)
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