[PD] weighted average (or ?)

[tim vets]

Ah right, an unnecessary step ofcourse.
but I do find it easier to understand that way, and you can adapt that '1'
to the desired sum directly...

Tim

2010/6/16 Funs Seelen <funsseelen at gmail.com>

> x / y
> or
> x * (1 / y)
> What's the difference?
> Funs
>
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