[PD] Bang order entry
Matteo Sisti Sette
matteosistisette at gmail.com
Tue Aug 17 17:52:40 CEST 2010
I feel like I'm missing a simpler way, but this one should do the trick
The delay amount determines the maximum time that can elapse between the
bangs of the two sensors. If a single bang is received from one sensor
and the other doesn't arrive within that time, the "orphan" bang will be
Is it what you were looking for?
On 08/17/2010 03:51 PM, João de Brito Rocha Reis Vidigal wrote:
> As it is coming from the arduino firmata, the only way I know is that
> the signal inputs a bang.
> So I'll have 2 bangs being hit with a delay between them. this delay
> depends on the speed of the body crossing the sensors and its size!
> calling them bang1 and bang2, if the order is bang1 then bang2 = coming
> in, if it is bang2 then bang1 it means coming out.
> the thing is I think I have to pair the hits to set an order and I just
> don't know how to pair them and read it to then bang an "in" or an "out".
> On 17 Aug 2010, at 14:29, Andrew Faraday wrote:
> what form is this coming into pd in?
> If it's a list (such as (door_crossing in) or (door_crossing out))
> then you could parse it down with routes
> [route door_crossing] (removes the first item in the list, if it's
> [sel in out] (the first two inlets will be a bang if it's in or out
> Not sure how else you might be getting the data into pd
>> From: jbvidigal at gmail.com <mailto:jbvidigal at gmail.com>
>> Date: Tue, 17 Aug 2010 13:45:53 +0100
>> To: pd-list at iem.at <mailto:pd-list at iem.at>
>> Subject: [PD] Bang order entry
>> Hi again.
>> Here goes another problem!
>> Ok. So I'm working with Arduino firmata here...
>> To expose to problem in a simple way, I have 2 sensors that are
> detecting a door crossing.
>> The 2 detectors give an order to the door crossing: coming in or going
>> Now I just don't know how I can translate that to bang 2 different
> [bang( depending on if someone's comming in or going out!
>> Can you help me with that!?
>> Joao Vidigal
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