[PD] Non-Linear Quantization / Bitcrush

[brandon zeeb]

Great!  Unfortunately, I'm not entirely sure how to realize this in Pd.  Can
you help me out with a little example?

Thanks

On Tue, Nov 2, 2010 at 2:37 PM, Ludwig Maes <ludwig.maes at gmail.com> wrote:

> So you want amplitude 'a' dependant quantization size 'q' ? take your
> chosen q(a); in your example it seems you want a simple line:
> q=q(0)-k*a;
> define f(a) as integral of 1/q from a=0 to a; also calculate the
> inverse of f(a) i.e. a(f);
>
> now for each sample do: out=a(round(f(in))) where round is any floor
> or the like...
>
> have fun!
>
> ps:
>
> in your example: q=q0-k*a with for example q(0)=0.001 and
> q(0.8)=0.0001: q:=0.001-0.0009/0.8*a
> then f=2558.427881-1111.111111*ln(10.-9.*a)
> and inverse=easy
>
>
> On 2 November 2010 19:20, Ludwig Maes <ludwig.maes at gmail.com> wrote:
> > This is pretty easy actually, I use such things mostly to guide my
> > rhythmical quantization...
> >
> > On 2 November 2010 19:19, brandon zeeb <zeeb.brandon at gmail.com> wrote:
> >> This is even better.  If I could minimize the jumps around Y = 0.5 to
> -0.5
> >> It'll be exactly what I'm looking for... or a start at least.
> >>
> >> Do you see what I mean now?  See how the amount of quantization changes
> with
> >> Y and a minimum quantization value?
> >>
> >> I think I'm getting towards the answer now...
> >>
> >> --
> >> Brandon Zeeb
> >> Columbus, Ohio
> >>
> >>
> >
>



-- 
Brandon Zeeb
Columbus, Ohio
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