[PD] To divide a number in random parts
az at zankapfel.org
Thu Mar 3 21:22:38 CET 2011
You could try this approach(I also attached a patch with it):
48 = 4 * 10 + 1 * 8
so you use
n2 = 10 - n1
n3 = random(10)
n4 = 10-n3
n9 = random(8)
n10 = 8 - n9
On 03.03.2011 02:20, Caio Barros wrote:
> Hey guys, long time since I posted here.
> I've been trying to think a way to divide a number into random parts.
> Let me explain myself better:
> I'm writing a piece where I want 10 chords played during 48 seconds but the
> duration of each chord should be different.
> So I'm trying to figure out a way to divide 48 into 10 unequal parts, I think
> using random numbers should be the best way but the difficulty is to get 10
> random numbers wich summed give 48.
> Since I'm not expert at math maybe someone can help me.
> I want to do this operation with other numbers, therefore a pd patch would be great.
> Pd-list at iem.at mailing list
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