[PD] backwards ead~

[Stephan Elliot Perez]

Thanks for your response.  I tried to apply the branching principal using
the equation from the [exact-ead~] by having the envelope go to 1 and then
to 2 instead of 0, using min 1 and max 1 to create a branch, using an
expression to convert the ascending numbers over 1 into descending numbers
under 1, and then jumping to 0.  I think the problem is that, during the
switches, two 1s are sent at the same time, leading to a 2 (as seen in the
graph), where I actually need a 0...

-Stephan

On Mon, May 30, 2011 at 8:34 PM, Andy Farnell <padawan12 at obiwannabe.co.uk>wrote:

>
>
>
> You might be able to easily get that behaviour by
> quickly editing the example I gave you.
>
> The maths is really geometry.
>
> There are a few things that can be done as time domain
> transforms when thinking about envelopes and suchlike
> in this way.
>
> 1) Flip it around zero with [*~ -1]
> 2) Invert arithmetically wrt 1.0 using [sig~ 1][-~]
> 3) Get the [min~] or the [max~] wrt another value
> 4) Clamp at a value using [clip~] ... is special case of (3)
> 5) Shift by an amount using [-~] or [+~]
> 6) Scale by some factor with [*~]
>
> IIRC the idiom for a two stage envelope like that is
> to use [min~]/[max~] to create a split point and treat
> each of the two branches differently (you can do piecewise
> waveform construction the same way).
>
> If you want time symmetry then have the [vline~] go to 1.0
> and back to [0.0] and just use one of the branches.
>
>
>
> On Mon, 30 May 2011 18:45:55 +0200
> Stephan Elliot Perez <dreamoftheshoreofanotherworld at gmail.com> wrote:
>
> > Greetings,
> >      Thank you for your responses.  I tried your suggestion, hardoff, and
> > the result is the attached [ead-reverse~].  Unfortunately, the expression
> > behaves differently with this [vline~]-construction as with the
> [phasor~].
> > Here, if 1 is entered into the right input of [expr~], the result is an
> > envelope whose steepness becomes exponentially smaller while ascending
> and
> > exponentially greater while descending (if near 0, the opposite form is
> > produced and values between 1 and 0 produce a divided, confused form). I
> > however wish to produce an envelope that becomes exponentially steeper
> both
> > ascending and descending.
> >      My problem with this [expr~] as well as with Mr. Farnell's patches
> is
> > that I do not quite understand the math behind them.  Any ideas?
> >
> > Best regards,
> > Stephan Elliot Perez
> >
> >
> > On Fri, May 27, 2011 at 5:54 PM, hard off <hard.off at gmail.com> wrote:
> >
> > > instead of the [phaser~], send a [line~] (or [vline~]) signal.
> > >
> > > for example:
> > >
> > > [1, 0.5 500, 0 1000 500(
> > > |
> > > [vline~]
> > >
> > >
> > > like most of my patches, i don't think i originally made that one,
> someone
> > > else posted it, and i just copied.   ;)
> > > must have been a long time ago though, cos i barely remember it.
> > >
> > >
> > >
> > >
> > > On Sat, May 28, 2011 at 12:24 AM, Stephan Elliot Perez <
> > > dreamoftheshoreofanotherworld at gmail.com> wrote:
> > >
> > >> Greetings,
> > >>        I wish to produce a wave form with the opposite form of the
> normal
> > >> ead~ wave (the curves become exponentially steeper instead of
> flatter),
> > >> which I can achieve by entering a negative number into the phasor in
> hard
> > >> off's exact-ead~ patch, which I downloaded from the archive.  However,
> I
> > >> still want to be able to independently change the length of the
> ascent,
> > >> decline, and distance between waves as is possible with ead~.  Does
> anyone
> > >> know how I could do this, or possibly have access to an
> abstraction-version
> > >> of ead~?
> > >>
> > >> Best regards,
> > >> Stephan
> > >>
> > >>
> > >>
> > >> _______________________________________________
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> > >>
> > >>
> > >
>
>
> --
> Andy Farnell <padawan12 at obiwannabe.co.uk>
>
> _______________________________________________
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> UNSUBSCRIBE and account-management ->
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