[PD] creation arg, distinction between 0 and no arg, WAS Re: Splitting Objects

[Jonathan Wilkes]

When $1 exists and has the value 0:
[symbol $1-foo] = 0-foo

When there is no $1:
[symbol $1-foo] = \\$1-foo

Therefore not only can you tell if an argument was set to 0
in Pd vanilla, but you can fetch the entire list of args by
counting up from $1 until $n-foo = \\$n-foo.

There are subpatches and abstractions on this list that
use that method to fetch the args in Pd Vanilla.

There is probably also an external for every developer
who has needed this functionality in their own patches,
most of which are available in Pd-extended.

-Jonathan


>________________________________
> From: Hans-Christoph Steiner <hans at at.or.at>
>To: Cyrille Henry <ch at chnry.net> 
>Cc: pd-list at iem.at 
>Sent: Thursday, October 11, 2012 12:26 PM
>Subject: Re: [PD] creation arg, distinction between 0 and no arg, WAS Re:  Splitting Objects
> 
>Interesting.  But its not really useable with dollar args,
>unfortunately, where $@ is.
>
>[default_arg $1] won't tell you whether $1 was set or not since it'll
>show up as zero to defulat-arg.pd
>
>.hc
>
>On 09/25/2012 10:08 AM, Cyrille Henry wrote:
>> hello,
>> 
>> a dirty hack allow distinction between no argument and a 0 float arg.
>> see attachment.
>> cheers
>> c
>> 
>> 
>> Le 25/09/2012 15:45, Patrice Colet a écrit :
>>>
>>>> De: "Patrice Colet" <colet.patrice at free.fr>
>>>>> De: "Funs Seelen" <funsseelen at gmail.com>
>>>>
>>>>> Speaking about creation arguments: if none are given for
>>>>> abstractions
>>>>> the default value is always "0" (at least I never figured out a way
>>>>> to
>>>>> give another default value *). For C-objects it is possible to use
>>>>> any
>>>>> float value as default.
>>>>
>>>>
>>>> [loadbang]
>>>> |
>>>> [$1]
>>>> |
>>>> [sel 0]
>>>> |
>>>> [my default value(
>>>>
>>>
>>> indeed it doesn't seem possible to set a default value and keep 0 as
>>> another value
>>>
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