[PD] put the argument of an abstraction in a message

[Charles Henry]

The arguments start from $1.  $0 is a unique identifier per instance
of an abstraction.
The $1,...,$N strings work differently in messages and objects.  $0
does nothing inside messages.

Just create an object [$1], send it a bang, and it dumps out the 1st
argument of the abstraction it's in.  I use it this way for floats.  I
think you need to declare it differently for strings/symbols.  How
about [symbol $1]?

Chuck

On Mon, Oct 15, 2012 at 10:19 AM, Charles Goyard <cg at fsck.fr> wrote:
> Hi list,
>
> I have an abstraction named "overlap". It takes an argument, such as
> "first" or "second".
>
> This abstraction outputs a list. I would like this list to contain the
> argument. I tried with $0 from inside the abstraction to no avail. It
> looks like $0 is available only to send and receive ?
>
> Maybe this sounds obvious, but I can't find the answer.
>
> Thanks,
>
> --
> Charlot
>
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