[PD] put the argument of an abstraction in a message

[Jack]

[list append] works with floats and symbols.
++

Jack



Le 15/10/2012 17:39, Charles Henry a écrit :
> The arguments start from $1.  $0 is a unique identifier per instance
> of an abstraction.
> The $1,...,$N strings work differently in messages and objects.  $0
> does nothing inside messages.
>
> Just create an object [$1], send it a bang, and it dumps out the 1st
> argument of the abstraction it's in.  I use it this way for floats.  I
> think you need to declare it differently for strings/symbols.  How
> about [symbol $1]?
>
> Chuck
>
> On Mon, Oct 15, 2012 at 10:19 AM, Charles Goyard <cg at fsck.fr> wrote:
>> Hi list,
>>
>> I have an abstraction named "overlap". It takes an argument, such as
>> "first" or "second".
>>
>> This abstraction outputs a list. I would like this list to contain the
>> argument. I tried with $0 from inside the abstraction to no avail. It
>> looks like $0 is available only to send and receive ?
>>
>> Maybe this sounds obvious, but I can't find the answer.
>>
>> Thanks,
>>
>> --
>> Charlot
>>
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