[PD] Scaling values in pd

Jm Jones juanmjv at gmail.com
Tue Sep 3 18:12:03 CEST 2013


jaja, "you can do the math". well, obviously we can always do the math, but
he was asking for that particular object. anyway, i appreciate the math
examples, surely they empower my brain : )

to the original question, as mentioned above, the object is in pd extended


2013/9/3 Mario Mey <mariomey at gmail.com>

> El 03/09/13 10:11, Lorenzo Sutton escribió:
>
>  On 03/09/2013 14:06, Mario Mey wrote:
>>
>>> IOhannes, you are right only in these cases:
>>>
>>> 0 127 0 500
>>> 0 300 0 1
>>> ...
>>>
>>> But, if I need:
>>>
>>> 50 10 0 500|
>>>
>> (assuming you want to map have 50 mapped to the 'minimum'):
>> |
>> [- 10]
>> |
>> [t b f]
>> |   /
>> [-  ]
>> |
>> [* 12.5]
>> |
>>
>>  3000 -3000 0.5 0.6
>>>
>> [* -1]
>> |
>> [+ 3000]
>> |
>> [/ 60000]
>> |
>> [+ 0.5]
>>
>
> Yes, you can make this math every scale you need... or use an abstract
> that does the same automatically. In my patch, I use 284 lin-eq-conv
> objects. I didn't want to think how to make that math... and change
> everytime (normally, I create a lin-eq-conv and change its values a lot of
> times).
>
> Best.
>
>
>
>
>>  ...
>>>
>>> I will need a "linear equation conversion". As I wrote in last mail, I
>>> was needing something like this, first in ActionScript... then in Python...
>>> but I never could did it. Now, I needed again in Pd... so, I made
>>> lin-eq-conv.pd with extrapolation and lin-eq-conv-clip.pd for clipped
>>> values. I made it as neat as I could, to see how it works. Using x0-x1 and
>>> y0-y1, it uses expr to get "a" and "b" at load. Then, it only computes "aX
>>> + b = Y".
>>>
>>> I attach the lin-eq-conv.pd, lin-eq-conv-clip.pd and lin-eq-conv-help.pd.
>>>
>>> Also, I have some issues using [autoscale]. I start giving values and it
>>> outputs only 1. Then, I start to down the input and, then, it shows the
>>> real output. Maybe it's about this version (0.43.4 Pd-Extended 64bits).
>>>
>>> PD: translated to Python:
>>>
>>> |def lin_eq_conv(x, x0, x1, y0, y1):
>>>    a = (y0 - y1) / (x0 - x1)
>>>    b = (a * x0) + y0
>>>    return a * x + b|
>>>
>>>
>>>
>>>
>>> El 03/09/13 03:32, IOhannes zmölnig escribió:
>>>
>>>> On 09/02/2013 06:17 PM, hghoyer wrote:
>>>>
>>>>> Hi,
>>>>>
>>>>> in Max/MSP there is an object for simple scaling.
>>>>>
>>>>> If you create in MAX these object with this arguments:
>>>>>
>>>>> [scale 0 127 0 500] incomming messages from 0 to 127 are automatically
>>>>> scaled from 0 to 500...
>>>>>
>>>> honestly i'm of the firm conviction that you should learn how scaling
>>>> works: it really is only a matter of adding, multiplying, dividing,
>>>> subtracting - stuff you should heave learned in primary school.
>>>>
>>>> as frank pointed out, this should do for you:
>>>>
>>>> |
>>>> [/ 127]
>>>> |
>>>> [* 500]
>>>> |
>>>>
>>>> if you find it too tedious to do the maths over and over again, you
>>>> might want to create an abstraction.
>>>>
>>>>
>>>> being able to solve trivial problems like this will surely empower you
>>>> to solve more complex problems :-)
>>>>
>>>> gamsdr
>>>> IOhannes
>>>>
>>>>
>>>>
>>>>
>>>>
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>>>
>>>
>>>
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>>
>>
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>
>
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-- 
JM Jones
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