[PD] Multiplying 2 variables
looplog at gmail.com
Thu Nov 28 11:52:13 CET 2013
So now I'm confused. What is the issue with Sebastián's original approach?
On Thu, Nov 28, 2013 at 6:33 PM, Lorenzo Sutton <lorenzofsutton at gmail.com>wrote:
> On 28/11/2013 11:20, michael noble wrote:
>> On Thu, Nov 28, 2013 at 5:21 PM, sebarocker at gmail.com
>> <mailto:sebarocker at gmail.com> <sebarocker at gmail.com
>> <mailto:sebarocker at gmail.com>> wrote:
>> I know that the multiplying object stores two values (left inlet and
>> right inlet) and performs the operation when both are stored or
>> when a bang is sent to the left inlet.
>> Not really. As lorenzo said, PD has strict rules regarding inlets and
>> order or execution. The [* ] only stores the value of the right inlet.
>> Any value sent to the left inlet will not be stored,
> Actually it is. The difference is that while a value coming in the right
> inlet will *only* be stored, with a value in the left inlet the value will
> be stored, the operation perfomed ( in this case multiplication) and the
> result output through the outlet.
> To try this out connect a numberbox and a bang to the left inlet, send a
> value and then send a bang, you see that the last value sent was also
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