[PD] get sinusoid from a sine and a cosine oscillator
Alexandros Drymonitis
adrcki at gmail.com
Thu Jan 30 17:58:32 CET 2014
On Thu, Jan 30, 2014 at 6:36 PM, Charles Z Henry <czhenry at gmail.com> wrote:
> That's the point I was making. By (x,y)->x I mean that you'd just use
> the x (cosine table) for example. The easiest projection is to throw away
> axes :)
>
> If you're making shapes as repeated paths in 2-D, then taking a projection
> (along an axis x y or any rotation of x,y) will generate a signal that
> makes sense and generalizes, creating simple sinusoids for circles and
> complex tones for different shapes.
> The pitch would vary by how fast the path is repeated, and the timbre
> would vary according to the shape. The amplitude would vary by the size of
> the shape. Those are simple rules--and may not be what you're interested
> in--but it would be consistent. For example, using a square in it's normal
> rotation and projecting along x or y alone, you'd get a "square wave".
>
> If you want to use a contribution from both of your axes, you can just sum
> them together. (x+y)*sqrt(2)/2 is just a projection along the line x-y=0
>
Can't really try it right now, but just to be sure, the last equation is to
be interpreted like this: (x+y)*(sqrt(2)/2) or like this:
((x+y)*sqrt(2))/2?
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