[PD] can [bp~] be obtained with biquad coefficients?
vboehm at gmx.ch
Fri Apr 11 21:46:18 CEST 2014
On 11.04.2014, at 16:48, Alexandre Torres Porres wrote:
> ""last" and "prev" are the last two _output_ samples.
> i don't know fexpr~ very well, but it looks like you try to access the last _input_ samples."
> In [fexpr~] you can access input samples with $x variables and output samples with $y. So you're correct. I'm going for the input samples.
> But I did it because I believe "last" and "prev" in this formula are in fact about input samples.
no, and it's pretty easy to see that from the code you quoted:
> > t_sample output = *in++ + coef1 * last + coef2 * prev;
> > *out++ = gain * output;
> > prev = last;
> > last = output;
after all it's a resonating filter and therefore needs a feedback path.
so it somehow has to take outgoing samples back in.
> So I feel pretty strong about getting this [fexpr~] right. Is there anything I did not take into consideration?
yes, calculate coef1, coef2 and gain by using the formulas from the code,
change the [fexpr~] to something like [ fexpr~ $x + ($f2 * $y[-1]) + ($f3 * $y[-2]) ],
(where $f2 and $f3 would be coef1 and coef2 resp.)
apply the gain factor afterwards,
and you are done.
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