[PD] Vanilla replacement for tanh~

Charles Z Henry czhenry at gmail.com
Thu Jul 2 21:40:40 CEST 2015


On Thu, Jul 2, 2015 at 2:31 PM, Cyrille Henry <ch at chnry.net> wrote:
> hello,
>
> Le 02/07/2015 21:06, Pagano, Patrick a écrit :
>>
>> Is there a way i can replace something for tanh~
>
>
> sin~ / cos~
>
> sin~ is a [+~ 0.25] and a [cos~]
>
> cheers
> c

That's tan~
tanh(x) = (e^x - e^-x)/(e^x + e^-x)

In vanilla, you should maybe just use pow~ or exp~ and build the whole formula.

Chuck


>
>>
>>
>> and inits in Vanilla 46?
>>
>>
>> please help!
>>
>>
>> pp
>>
>>
>> /Patrick Pagano B.S, M.F.A/
>> Audio and Projection Design Faculty
>> Digital Worlds Institute
>> University of Florida, USA
>> (352)294-2020
>>
>>
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