[PD] How does vline~ work under the hood?

Alexandre Torres Porres porres at gmail.com
Fri Oct 16 22:42:39 CEST 2015


> Does vline also have to wait for a block boundary when first triggered?

this is probably cleared out and not sure if this is the question, but
vline~ will respect the schedule timing of events with a delay of one
block, meaning that it'll convert the events to audio rate but only for the
next block.

now I wonder what happens for blocks that are smaller than 64

cheers

2015-09-26 9:24 GMT-03:00 i go bananas <hard.off at gmail.com>:

> Thanks,
>
> I guess here is my question put better:
>
> If i make a line and a vline object, and feed them both a [1, 0 50(
>  message, they perform differently.  The line object jumps around,
> presumably cos it is tied to block boundaries.
> But the vline always triggers exactly the same.
>
> It's as if somehow the vline~ works outside of the block structure.  Does
> it actually do that?  Say you're at sample 47 of a 64 sample block, does
> vline jump the queue and trigger right then?
>
> Or i guess, even more succinctly, i was assuming that everything in pd got
> triggered in blocks.  Is that the case?  Does vline also have to wait for a
> block boundary when first triggered?
>
> Sorry, there's obviously some 'aha' moment i'm failing to have here.
>
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