[PD] Moving Sum object?

[Alexandre Torres Porres]

not sure this is working either, I'm getting negative values when testing
it with count~ (only positive values)

2015-12-08 10:30 GMT-02:00 Christof Ressi <christof.ressi at gmx.at>:

> It certainly is and I have no idea how that happened :-D. but it has no
> effect whatsoever. just delete the connection.
>
>
> Gesendet: Dienstag, 08. Dezember 2015 um 13:20 Uhr
> Von: "Alexandre Torres Porres" <porres at gmail.com>
> An: "Christof Ressi" <christof.ressi at gmx.at>
> Cc: "pd-list at lists.iem.at" <pd-list at lists.iem.at>
> Betreff: Re: Re: [PD] Moving Sum object?
>
> what was the purpose of the output from the max object into rpole~ in your
> patch? that's a bug, right?
>
> cheers
>
> 2015-12-08 9:50 GMT-02:00 Christof Ressi <christof.ressi at gmx.at>:
>
> Or are you talking about a object that outputs the sum as a message? In
> that case just use [cmavg~] or [maverage~] with [snapshot~]. If you just
> want the sum of a signal vector, there are some objects in zexy that will
> do the job, like [avg~] or [pack~]+[sum]
>
>
> Gesendet: Dienstag, 08. Dezember 2015 um 12:41 Uhr
> Von: "Christof Ressi" <christof.ressi at gmx.at[christof.ressi at gmx.at]>
>
> An: "Alexandre Torres Porres" <porres at gmail.com[porres at gmail.com]>
> Cc: "pd-list at lists.iem.at[pd-list at lists.iem.at]" <pd-list at lists.iem.at[
> pd-list at lists.iem.at]>
> Betreff: Re: [PD] Moving Sum object?
>
> Well, a linear moving average filter is just something that  sums a series
> of samples. If you don't want the average but rather the true sum, either
> multiply the output by the number of samples or take my abstraction and get
> rid of the [/~] object.
>
>
> Gesendet: Dienstag, 08. Dezember 2015 um 12:21 Uhr
> Von: "Alexandre Torres Porres" <porres at gmail.com[porres at gmail.com]>
> An: "Christof Ressi" <christof.ressi at gmx.at[christof.ressi at gmx.at]>
> Cc: "Matt Barber" <brbrofsvl at gmail.com[brbrofsvl at gmail.com]>, "
> pd-list at lists.iem.at[pd-list at lists.iem.at]" <pd-list at lists.iem.at[
> pd-list at lists.iem.at]>
> Betreff: Re: Re: [PD] Moving Sum object?
>
> cool guys, but i was asking for an average "sum" object :)
>
> 2015-12-08 9:19 GMT-02:00 Christof Ressi <christof.ressi at gmx.at>:Hey Matt,
>
> there's no need for the feedback path (and therefore no [block~ 1] ;-))
>
> Just use the following formula:
>
> y[n] = (y[n-1] - x[n-k])/k
>
> where k is the number of samples to be averaged (must be at least 1). see
> the patch I sent to Alex in my last mail.
> it uses [rpole~ 1] for the y[n-1] part and [z~ k] for the x[n-k] part (you
> can replace the latter one with a [delwrite~] [delread~] pair to make it
> purely vanilla).
>
> The funny thing about linear moving average filters is, that although it
> can be implemented as a recursive filter (like in both our patches), it is
> still a FIR filter (and therefore it defeats the notion that recursive
> filters are always IIR filters). The impulse response is just a rectangular
> pulse and therefore finite.
>
>
>
> Gesendet: Dienstag, 08. Dezember 2015 um 07:13 Uhr
> Von: "Matt Barber" <brbrofsvl at gmail.com>
> An: "Alexandre Torres Porres" <porres at gmail.com>
> Cc: "pd-list at lists.iem.at" <pd-list at lists.iem.at>
> Betreff: Re: [PD] Moving Sum object?
>
> Something like this? Almost completely untestsed. :D
>
> On Tue, Dec 8, 2015 at 12:20 AM, Alexandre Torres Porres <porres at gmail.com>
> wrote:
>
> Talking about averages I wonder if we have an object that sums (in a
> moving average fashion) a series of samples
>
> cheers
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