[PD] 1 / 0 = 0?

[Matt Davey]

Just don’t allow your function to blow up in the first place.

On Thursday, May 24, 2018, William Huston <williamahuston at gmail.com> wrote:

> I have a function which blows up at a certain point, moves to infinity.
> In this case, it is basically 1/0.
>
> I was a little surprised to find that 1/0 = 0 (according to Pd).
> I was expecting NaN, or an overflow condition would could be trapped.
>
> So what I have to do is examine the *input* for the values
> which will blow up my function, and set a flag. While this
> is easy in this single case, it is awkward in the general case.
>
> This seems somewhat broken to me.
> Is this a bug?
>
> Thanks
> BH
>
>
> --
> William Huston:  WilliamAHuston at gmail.com
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