[PD] bang on phasor~ wrap

me.grimm megrimm at gmail.com
Mon Mar 4 14:11:21 CET 2019


>> [fexpr~ abs($x[0] - $x[-1]) > 0.5]
>> [threshold~ 0.5 0 0.5 0]

sick

On Sat, Mar 2, 2019 at 7:31 PM Alexandre Torres Porres <porres at gmail.com>
wrote:

> connect output of [phasor~] into:
>
> [fexpr~ abs($x[0] - $x[-1]) > 0.5]
>
> then use:
>
> [threshold~ 0.5 0 0.5 0]
>
> Em sáb, 2 de mar de 2019 às 11:05, Claude Heiland-Allen <
> claude at mathr.co.uk> escreveu:
>
>> On 2019-03-02 13:20, Orm Finnendahl wrote:
>> >  is there some easy way in vanilla pd to get a bang on each phasor~
>> > wraparound which doesn't involve polling with snapshot~?
>>
>> https://lists.puredata.info/pipermail/pd-list/2006-12/044634.html
>>
>> --
>> https://mathr.co.uk
>>
>>
>>
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