[PD] Vanilla method for symbol -> float

Henri Augusto Bisognini msndohenri at hotmail.com
Sat Oct 12 21:55:11 CEST 2019


Worth noting that this solution only works if the numerator and denumerator are single-digit.

________________________________
De: Pd-list <pd-list-bounces at lists.iem.at> em nome de Alexandre Torres Porres <porres at gmail.com>
Enviado: sábado, 12 de outubro de 2019 16:26
Para: Ingo Stock <mail at ingostock.de>
Cc: Pd-List <pd-list at lists.iem.at>
Assunto: Re: [PD] Vanilla method for symbol -> float

that's a clever one :)

Em sáb, 12 de out de 2019 às 03:30, Ingo Stock <mail at ingostock.de<mailto:mail at ingostock.de>> escreveu:
Like this?


On 12.10.19 09:01, João Pais wrote:
> Hi list,
>
> I was trying something without succes, and couldn't find any
> documentation for it as well.
>
>
> I wanted to split the symbol 2/4 to separate the numbers on both sides
> of the / . No problem using [list fromsymbol] and [list tosymbol] in
> doing that. But, afterwards I can't find a way of turning the symbol
> back to a float, except using an external. Is there any special hack
> somewhere for this?
>
>
> Best,
>
> JOao
>
>
>
>
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