[PD] what happens when you send signals between 0..1 instead -1..1 to dac?

Lucas Cordiviola lucarda27 at hotmail.com
Mon Mar 2 07:42:17 CET 2020


>  I guess there's a math foundation here that would justify the need 
> for a -1..1 correct signal range...


Is just a convenience.

16bit or 24bit audio files have totally different numbers to represent 
the start, middle and end of the same sine wave.

Why would you want Pd to have 0 as one side of the sample's limits?



Mensaje telepatico asistido por maquinas.

On 3/2/2020 12:42 AM, Fede Camara Halac wrote:
> Thanks Christof and Lucas for your replies!
>>
>> The Amp and the Speaker will just work on "one half" of their normal 
>> area. (50% of its audio loudness).
>>
> Exactly, that is the difference I hear in loudness.
>>
>> It shouldn't hurt the amp or the speaker as long as you don't try to 
>> pump up the volume. You might break the speaker if you increase too 
>> much the volume. (it will sound soft but you are pushing it too much 
>> to one of its extremes).
>>
> Indeed, this is an important warning that should be in the docs (if 
> it's there other than getting rid of DC offset, I must have missed it)
>
>> Personally, I like to play it safe and add a [hip~ 5] as a DC filter 
>> before my [dac~] :-)
>
> I do this, too, just by (blindly) following the pd manual and 
> helpfiles... perhaps this calls for a tiny adjustment to the [dac] 
> object to always implement a hipass (with perhaps a flag to revert to 
> a non-hipass-5 enabled  [dac]). Just a thought, but one that could be 
> easily argued against given pd's agnostic qualities.
>
>> You might use your DAC to send control voltages for a modular 
>> synthesizer, for example. 
>
> I have never tried this, but I guess it might be an edge case, and 
> quite an interesting one.
>
>
> So, if I want to get more technical as to what exactly happens to the 
> speakers when sending such "malformed" or "halfformed?" signals, do 
> you know where I can find good sources that would explain this? I 
> guess there's a math foundation here that would justify the need for a 
> -1..1 correct signal range... an age old one that probably relates to 
> the  Nyquist theorem... but I can't see how.
>
>
> In any case, thanks again for the quick replies!
>
> Best,
>
> f
>
>>
>
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