[PD-ot] using "-send" and shell-variables

[Hans-Christoph Steiner]

On Mar 14, 2006, at 10:53 AM, IOhannes m zmoelnig wrote:

> Hans-Christoph Steiner wrote:
>>
>> Both above scripts work for me, I think the problem lies elsewhere.
>
> which shell are you using? bash? tcsh? something else??
> have you tested on linux or osX?

/bin/sh on OSX.  But I think that its all the same, that code is so old.

>> quotes mean literal, so no expansion of variables is done.  Quotes
>> inside of quotes are just characters, only the outer most count  
>> (AFAIK).
>>
>> VAR=test
>>
>> echo '$VAR'    prints: $VAR
>> echo "$VAR"    prints: test
>> echo '"$VAR"'  prints: "$VAR"
>> echo "'$VAR'"  prints: 'test'
>>
>> If that helps at all.  You might want to try sticking with only " and
>> escaping the ones inside:
>>
>> echo "\"$VAR\""  prints: "test"
>
> unfortunately (since it doesn't help me here), i know all this.
> the problem -as i see it- is, that my quotes somehow destroy the  
> atomic
> structure of the enquoted stuff.
>
> e.g. i do:
> <snip>
>  pd -send "pd quit"
> </snip>
> pd now gets 2 args '-send' and 'pd quit'.
> the '-send' tells pd that the next arg will be a message to shout. the
> message 'pd quit' is then sent (and received by 'pd')
>
> however, when i do
> <snip>
> OPTIONS="-send \"pd quit\""
> pd ${OPTIONS}
> </snip>
>
> here it seems that pd gets 3(!) args '-send', '"pd' and 'quit"'.
> pd therefore shouts and empty message to the receiver '"pd' and then
> tries to open (since it is a non-flagged argument) the patch 'quit"'.
> of course there is no receiver '"pd' and no patch 'quit"'.
>
> i'm still stupified...

can you post the actual script?  Its hard to tell what's happening  
based on the snippets.

.hc

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