[PD] lists and sums

[stm_sq^n]

Hello IOhannes,

Imz> if you have lists of varying length you can use zexy's
Imz> [mean], which gets (1/n)*sum(), and multiply it with the [length] of the 
Imz> list...

thanks, it's much better this way than using the [unpack ] and [+ ]
combo.

thanks !

stm