[PD] converting decimal to binary
Federico
xaero at inwind.it
Fri Jun 30 11:18:23 CEST 2006
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Chuckk Hubbard wrote:
> It is an approximation, and gets closer and closer, and it works if
> you start with ANY 2 positive numbers and make a Fibonacci-esque
> series from them. You could start with 2 and 417, then 419, 836,
> 1255, etc, and gradually the ratios of consecutive members of the
> series start to approach the golden ratio.
yes, with fibonacci serie it is an approximation.
but you now discovered the rule:
> The golden ratio is defined by
> x=1/x + 1
that is:
1/1.618 = 0.618 and 1/0.618 = 1.618
you could write that formula as a 2nd grade equation:
1/x = x - 1
x*(1/x) = (x - 1)*x // multiply by x
1 = x^2 - x
then write as:
x^2 - x - 1 = 0
so, applying the formula for solving 2nd g eq:
x[1,2] = (1 ± sqrt(5))/2
you got *THE* magic ratio:
x1 = 1.618033989...
x2 = -0.618033989...
(and the approximation depends on your calculator... hehe ;)
1.61803398874989484820458683436563811772030917980576286213544862270526
is enough?
> when you take, for instance, 13/8, that is 1 + 5/8... or 21/13 is 1 +
> 8/13... 34/21 is 1 + 13/21, because of the way you obtain each number.
> Always 1 + the reciprocal of the previous ratio. So you will never
> quite reach the golden ratio, but you alternately go slightly higher
> and slightly lower, getting gradually closer.
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