[PD] Max's [rate~] implementation...
Lorenzo Sutton
lorenzofsutton at gmail.com
Fri Dec 7 13:12:46 CET 2012
On 06/12/12 15:31, Hans-Christoph Steiner wrote:
>
> Leaving out [rate~] should use less CPU since [rate~] doesn't have to
> do the analysis part, if I understand it correctly.
If I understand correctly what rate~ does, the argument is actually a
factor, so I thnk the frequency for the phasor~ has to be 1 / factor...
So for example
[rate~ 1.5]
is [phasor~ 0.666667]
Lorenzo.
>
>
>
>
> .hc
>
> On Dec 6, 2012, at 9:24 AM, Alexandros Drymonitis wrote:
>
>> Don't think I really follow. Each [rate~] actually outputs a
>> [phasor~] with a different frequency (different frequency ratio), all
>> driven by the same [phasor~]. How can you send a value from one
>> number box to all [phasor~]s?
>>
>>
>> On Thu, Dec 6, 2012 at 4:18 PM, Hans-Christoph Steiner <hans at at.or.at
>> <mailto:hans at at.or.at>> wrote:
>>
>>
>> Why not just use a phasor~ per rate~ and then have the frequency
>> of all them controlled by the same number box?
>>
>> .hc
>>
>> On Dec 6, 2012, at 8:57 AM, Alexandros Drymonitis wrote:
>>
>>> copy this patch
>>> http://www.youtube.com/watch?v=6P4Ezz9aWa8&feature=plcp
>>>
>>>
>>> On Thu, Dec 6, 2012 at 3:55 PM, Simon Iten <itensimon at gmail.com
>>> <mailto:itensimon at gmail.com>> wrote:
>>>
>>> What are you trying to accomplish?
>>>
>>> On Dec 6, 2012 2:48 PM, "Alexandros Drymonitis"
>>> <adrcki at gmail.com <mailto:adrcki at gmail.com>> wrote:
>>>
>>> How can one implement Max's [rate~] in Pd? [rate~] takes
>>> a signal from a [phasor~] and according to its argument
>>> it scales the frequency (roughly speaking). So
>>>
>>> [phasor~ 1]
>>> |
>>> [rate~ 1.5]
>>>
>>> will actually give a [phasor~ 1.5]. I thought of [wrap]
>>> but that won't do the trick with non-integers.
>>> Any ideas?
>>>
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