[PD] Max's [rate~] implementation...

Lorenzo Sutton lorenzofsutton at gmail.com
Fri Dec 7 13:12:46 CET 2012


On 06/12/12 15:31, Hans-Christoph Steiner wrote:
>
> Leaving out [rate~] should use less CPU since [rate~] doesn't have to 
> do the analysis part, if I understand it correctly.

If I understand correctly what rate~ does, the argument is actually a 
factor, so I thnk the frequency for the phasor~ has to be 1 / factor... 
So for example

[rate~ 1.5]

is [phasor~ 0.666667]

Lorenzo.
>
>
>
>
> .hc
>
> On Dec 6, 2012, at 9:24 AM, Alexandros Drymonitis wrote:
>
>> Don't think I really follow. Each [rate~] actually outputs a 
>> [phasor~] with a different frequency (different frequency ratio), all 
>> driven by the same [phasor~]. How can you send a value from one 
>> number box to all [phasor~]s?
>>
>>
>> On Thu, Dec 6, 2012 at 4:18 PM, Hans-Christoph Steiner <hans at at.or.at 
>> <mailto:hans at at.or.at>> wrote:
>>
>>
>>     Why not just use a phasor~ per rate~ and then have the frequency
>>     of all them controlled by the same number box?
>>
>>     .hc
>>
>>     On Dec 6, 2012, at 8:57 AM, Alexandros Drymonitis wrote:
>>
>>>     copy this patch
>>>     http://www.youtube.com/watch?v=6P4Ezz9aWa8&feature=plcp
>>>
>>>
>>>     On Thu, Dec 6, 2012 at 3:55 PM, Simon Iten <itensimon at gmail.com
>>>     <mailto:itensimon at gmail.com>> wrote:
>>>
>>>         What are you trying to accomplish?
>>>
>>>         On Dec 6, 2012 2:48 PM, "Alexandros Drymonitis"
>>>         <adrcki at gmail.com <mailto:adrcki at gmail.com>> wrote:
>>>
>>>             How can one implement Max's [rate~] in Pd? [rate~] takes
>>>             a signal from a [phasor~] and according to its argument
>>>             it scales the frequency (roughly speaking). So
>>>
>>>             [phasor~ 1]
>>>             |
>>>             [rate~ 1.5]
>>>
>>>             will actually give a [phasor~ 1.5]. I thought of [wrap]
>>>             but that won't do the trick with non-integers.
>>>             Any ideas?
>>>
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>>
>
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