[PD] Negative input numbers for [pow] return 0

Joe White white.joe4 at gmail.com
Mon Apr 22 14:19:50 CEST 2013


Just realised putting a negative number into the [pow] object outputs '0'?!?

For example if I do:

[-1 (
[pow 2]

it returns 0, where I would expect it to return 1.

Is this a known limitation or bug? Are there any work arounds if I want a
variable power?

(I'm running Pd 0.44.1 on OS X Mountain Lion)

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