[PD] Negative input numbers for [pow] return 0

[IOhannes m zmoelnig]

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On 2013-04-22 14:19, Joe White wrote:
> Hi,
> 
> Just realised putting a negative number into the [pow] object
> outputs '0'?!?
> 
> For example if I do:
> 
> [-1 ( | [pow 2]
> 
> it returns 0, where I would expect it to return 1.
> 
> Is this a known limitation or bug?

it's most likely a feature that tries to protect you from things like:

[-1(
|
[pow 0.5]
|

> Are there any work arounds if I want a variable power?

urgh, i had hoped to never have to tell people to use [expr], but
there you go:

[-1\
|
[pack 0 2]
|
[expr pow($f1, $f2)]
|
[1\

vbmdf
IOhannes
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