[PD] Where is [paf~]?

[Alexandre Torres Porres]

Cool, do you mean one could do [paf~] with F13 example as an abstraction?

Cause F13 says the [paf~] external should work better, and I quote: "*The
frequency itself changes instantly, but the center/fundamental frequency
ratio waits for the next period. This gives a slight "chirp" if the
fundamental is abruptly raised a couple of octaves. There's no easy way
using Pd's built-in primitives to avoid this. Note however that there's a
"paf~" extern available which solves this problem better and, moreover,
runs much faster.*"

That's what made me wonder about it. So I guess, if you have it and the
patent is over, could be good just to upload it back ;)

Thanks

2015-01-14 18:26 GMT-02:00 Miller Puckette <msp at ucsd.edu>:

> I should fix this - I took down paf~ years ago when IRCAM complained.
> But the patent it expired so I can put it up now if it's worth putting up.
> But meanwhile, I'm not sure whether it's a good idea, since it's so easy
> to make the paf~ out of simpler Pd objects.  The only gain to having a
> paf~ object is that it runs faster - I'm not sure that justifies the
> maintenance.
>
> cheers
> Miller
>
> On Wed, Jan 14, 2015 at 03:48:29PM -0200, Alexandre Torres Porres wrote:
> > Hi, F13.paf.control mentions the existence of a [paf~] extern that I
> guess
> > should be in the extra folder of vanilla, but it ain't there.
> >
> > What happened to it?
> >
> > The readme.txt in extra on vanilla mentions also about a link to download
> > it at http://www.crca.ucsd.edu/~tapel - but this link is dead.
> >
> > Thanks
>
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