[PD] How does vline~ work under the hood?

Alexandre Torres Porres porres at gmail.com
Sun Oct 18 05:50:50 CEST 2015


i was wondering if it worked well with block sizes less than 64, I find
sometimes some object don't act well for such block sizes

but I tested it and vline is fine ;)

2015-10-16 19:51 GMT-03:00 Jonathan Wilkes <jancsika at yahoo.com>:

> Hi Alexandre,
> The [vline~] object can compute ramps with subsample accuracy,
> regardless of the block size.
>
> Though I might not understand the question.
>
> -Jonathan
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> On Friday, October 16, 2015 4:42 PM, Alexandre Torres Porres <
> porres at gmail.com> wrote:
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> > Does vline also have to wait for a block boundary when first triggered?
>
> this is probably cleared out and not sure if this is the question, but
> vline~ will respect the schedule timing of events with a delay of one
> block, meaning that it'll convert the events to audio rate but only for the
> next block.
>
> now I wonder what happens for blocks that are smaller than 64
>
> cheers
>
> 2015-09-26 9:24 GMT-03:00 i go bananas <hard.off at gmail.com>:
>
> Thanks,
>
> I guess here is my question put better:
>
> If i make a line and a vline object, and feed them both a [1, 0 50(
>  message, they perform differently.  The line object jumps around,
> presumably cos it is tied to block boundaries.
> But the vline always triggers exactly the same.
>
> It's as if somehow the vline~ works outside of the block structure.  Does
> it actually do that?  Say you're at sample 47 of a 64 sample block, does
> vline jump the queue and trigger right then?
>
> Or i guess, even more succinctly, i was assuming that everything in pd got
> triggered in blocks.  Is that the case?  Does vline also have to wait for a
> block boundary when first triggered?
>
> Sorry, there's obviously some 'aha' moment i'm failing to have here.
>
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