[PD] How does vline~ work under the hood?

[Jonathan Wilkes]

Hi Alexandre,
The [vline~] object can compute ramps with subsample accuracy, 
regardless of the block size.
Though I might not understand the question.

-Jonathan
 

 




 


   

  On Friday, October 16, 2015 4:42 PM, Alexandre Torres Porres <porres at gmail.com> wrote:
   

 > Does vline also have to wait for a block boundary when first triggered? 
this is probably cleared out and not sure if this is the question, but vline~ will respect the schedule timing of events with a delay of one block, meaning that it'll convert the events to audio rate but only for the next block.
now I wonder what happens for blocks that are smaller than 64
cheers
2015-09-26 9:24 GMT-03:00 i go bananas <hard.off at gmail.com>:

Thanks, 
I guess here is my question put better: 
If i make a line and a vline object, and feed them both a [1, 0 50(  message, they perform differently.  The line object jumps around, presumably cos it is tied to block boundaries.  But the vline always triggers exactly the same.  
It's as if somehow the vline~ works outside of the block structure.  Does it actually do that?  Say you're at sample 47 of a 64 sample block, does vline jump the queue and trigger right then?  
Or i guess, even more succinctly, i was assuming that everything in pd got triggered in blocks.  Is that the case?  Does vline also have to wait for a block boundary when first triggered?   Sorry, there's obviously some 'aha' moment i'm failing to have here.  
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