[PD] A 6th order hilbert transformer?

Alexandre Torres Porres porres at gmail.com
Thu Jun 23 06:24:11 CEST 2016


Awesome, I can code it based on that :) but which order is it?

I see it has 4 biquads, but it doesnt look like an 8th order because some
coefficients are zeroed out, so I'm confused.

Another question, does it work at any sample rate? This question is also
aimed to pd's hilbert~ abstraction by the way.

cheers

2016-06-22 17:27 GMT-03:00 katja <katjavetter at gmail.com>:

> Hi, Olli Niemitalou has coefficients published for a higher order
> 'hilbert transformer' on http://yehar.com/blog/, attached is [olli~]
> abstraction based on it.
>
> Katja
>
> On Wed, Jun 22, 2016 at 4:37 AM, Alexandre Torres Porres
> <porres at gmail.com> wrote:
> > Howdy, I'm working on a frequency shifter object (via single sideband
> > modulation / complex modulation).
> >
> > In Max they have a so called "6th order hilbert transformer with a
> minimum
> > of error". In Pd, the hilbert~ abstraction is 4th order. I'm copying the
> pd
> > abstraction for now, but I was hoping to use such a higher order filter
> and
> > also use- but I can't find a source for such a formula. Any help finding
> it?
> >
> > thanks
> >
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>
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